Mathematics
05802025–2027 syllabus

MATHEMATICS · CHAPTER 2

Algebra and graphs

Represent patterns, rearrange relationships, solve unknowns and connect equations to their graphs.

Core + Extended6 connected sectionsNotes only

LEARNING OBJECTIVES

By the end of this chapter, you should be able to:

  • substitute values and manipulate algebraic expressions
  • expand, factorise and complete the square
  • simplify algebraic fractions and apply index laws
  • solve linear, quadratic, fractional and simultaneous equations
  • solve and represent inequalities
  • find rules for sequences and use direct or inverse proportion
  • interpret practical, polynomial, reciprocal and exponential graphs
  • differentiate simple functions and use function notation

THE BIG IDEA

Represent patterns, rearrange relationships, solve unknowns and connect equations to their graphs.

Algebra replaces particular numbers with symbols so that one relationship can describe many situations. An equation states that two expressions have equal value; solving it means finding every value that makes that statement true.

Graphs give the same relationships a visual form. Intercepts show where a quantity becomes zero, gradients show rates of change, and intersections show values that satisfy two relationships at once.

01

SECTION 01

Expressions, expansion and factorisation

Terms are like terms only when their variable parts, including indices, match. Coefficients of like terms may be added or subtracted.

Expansion removes brackets by multiplying every term. Factorisation reverses expansion. Always look for a common factor before trying identities or quadratic methods.

KEY IDEAS

  • Difference of squares: a² − b² = (a − b)(a + b).
  • Perfect square: a² + 2ab + b² = (a + b)².
  • For ax² + bx + c, choose factors whose product is ac and whose sum is b, then group.
  • Completing the square rewrites a quadratic as a(x − p)² + q, revealing its turning point.
RULE 1
(a + b)(c + d) = ac + ad + bc + bd
RULE 2
a² − b² = (a − b)(a + b)
RULE 3
x² + 2px + p² = (x + p)²
Original worked example

Factorising 6x² + 7x − 3

  1. ac = 6 × (−3) = −18; choose 9 and −2 because their sum is 7.
  2. 6x² + 9x − 2x − 3
  3. 3x(2x + 3) − 1(2x + 3)
  4. (3x − 1)(2x + 3)

Answer: 6x² + 7x − 3 = (3x − 1)(2x + 3).

02

SECTION 02

Algebraic fractions and indices

Treat an algebraic fraction like a numerical fraction: factor before cancelling, use a common denominator for addition, and multiply by the reciprocal when dividing.

A factor may be cancelled only when it multiplies the whole numerator and denominator. State excluded values when a denominator could be zero.

KEY IDEAS

  • x² − 5x + 6 factors to (x − 2)(x − 3).
  • aᵐaⁿ = aᵐ⁺ⁿ, aᵐ/aⁿ = aᵐ⁻ⁿ and (aᵐ)ⁿ = aᵐⁿ.
  • Rewrite both sides with the same base to solve simple exponential equations.
RULE 1
a⁻ⁿ = 1/aⁿ
RULE 2
a¹⁄ⁿ = ⁿ√a
RULE 3
aᵐ⁄ⁿ = ⁿ√(aᵐ)
Original worked example

Simplifying (x² − 4)/(x² + x − 6)

  1. Factor the numerator: x² − 4 = (x − 2)(x + 2).
  2. Factor the denominator: x² + x − 6 = (x − 2)(x + 3).
  3. Cancel the common factor x − 2.

Answer: (x + 2)/(x + 3), where x ≠ 2 and x ≠ −3.

03

SECTION 03

Equations and changing the subject

Keep an equation balanced by performing the same valid operation on both sides. Clear fractions early when this makes the structure simpler.

Simultaneous equations share the same solution. Use elimination or substitution for two linear equations; substitute the linear equation into the non-linear one when a curve is involved.

Quadratics may be solved by factorisation, completing the square or the quadratic formula. A negative discriminant means there are no real roots.

KEY IDEAS

  • When changing the subject, undo operations in reverse order.
  • If the new subject appears more than once, collect its terms and factorise.
  • Check solutions in the original equation, especially when denominators are present.
RULE 1
x = (−b ± √(b² − 4ac))/(2a)
RULE 2
discriminant = b² − 4ac
Original worked example

Solving x² − 5x − 14 = 0

  1. Find two numbers with product −14 and sum −5: −7 and 2.
  2. Factorise: (x − 7)(x + 2) = 0.
  3. Set each factor equal to zero.

Answer: x = 7 or x = −2.

04

SECTION 04

Inequalities, sequences and proportion

Strict inequalities use open circles or broken boundary lines. Inclusive inequalities use closed circles or solid boundary lines. On region diagrams, follow the question's shading convention carefully.

A sequence rule can connect each term to the next or connect the position n directly to the term. Constant first differences indicate a linear sequence; constant second differences indicate a quadratic sequence; constant third differences indicate a cubic sequence.

An exponential sequence has a constant multiplier between consecutive terms. Mixed sequences may combine linear, quadratic, cubic or exponential patterns, so compare both differences and ratios.

In direct proportion, both variables change in the same scale direction. In inverse proportion, multiplying one variable by a factor divides the other by that factor.

KEY IDEAS

  • For a quadratic sequence, if the second difference is 2a, the n² coefficient is a.
  • Direct proportion: y = kxⁿ. Inverse proportion: y = k/xⁿ.
  • Find k from one known pair before using the model.
RULE 1
linear nth term = dn + c
RULE 2
y ∝ x² ⇒ y = kx²
RULE 3
y ∝ 1/√x ⇒ y = k/√x
Original worked example

Finding the nth term of 4, 9, 16, 25, …

  1. The terms are 2², 3², 4², 5², …
  2. At position n, the base is n + 1.
  3. Square the base.

Answer: The nth term is (n + 1)².

05

SECTION 05

Graphs and practical rates

On a distance–time graph, gradient is speed. A horizontal section means stationary. On a speed–time graph, gradient is acceleration and area under the graph is distance travelled.

Linear, quadratic, cubic, reciprocal and exponential families have distinctive shapes. Roots are x-intercepts; turning points are local maxima or minima; reciprocal graphs have asymptotes that the curve approaches.

Common function forms include powers axⁿ, combinations of up to three power terms and exponentials abˣ + c. A table of values should include enough points to show roots, turning points and asymptotic behaviour.

Equations can be solved graphically by reading x-intercepts or intersections. Graphical answers are estimates and should match the graph's scale.

KEY IDEAS

  • gradient = change in vertical quantity ÷ change in horizontal quantity
  • distance = area under a speed–time graph
  • A tangent estimates the instantaneous gradient of a curve.
Original worked example

Distance from a speed–time graph

  1. A vehicle accelerates uniformly from 0 to 18 m/s in 6 s.
  2. The region under this part is a triangle.
  3. Area = 1/2 × 6 × 18.

Answer: The vehicle travels 54 m during the acceleration.

06

SECTION 06

Differentiation and functions

Differentiation gives a formula for gradient. For each term axⁿ, multiply by n and reduce the power by one. A stationary point occurs where dy/dx = 0.

The second derivative can classify a stationary point: d²y/dx² > 0 indicates a local minimum and d²y/dx² < 0 indicates a local maximum. A sketch or the gradient on either side may also be used.

A function maps each allowed input to one output. The domain is the set of allowed inputs and the range is the resulting set of outputs.

An inverse function reverses the original mapping. A composite function such as gf(x) means apply f first, then g. Mapping diagrams can show inputs, outputs and whether a relation is a function.

KEY IDEAS

  • At a local maximum, the gradient changes from positive to negative.
  • At a local minimum, the gradient changes from negative to positive.
  • To find f⁻¹, write y = f(x), rearrange for x, then exchange x and y.
RULE 1
d/dx(axⁿ) = anxⁿ⁻¹
RULE 2
gf(x) = g(f(x))
Original worked example

Stationary point of y = x² − 6x + 11

  1. dy/dx = 2x − 6.
  2. Set 2x − 6 = 0, giving x = 3.
  3. Substitute: y = 9 − 18 + 11 = 2.
  4. The coefficient of x² is positive, so the curve has a minimum.

Answer: The minimum point is (3, 2).

QUICK CHAPTER SUMMARY

The ideas to carry forward

  • Collect only like terms and factorise fully.
  • Check restrictions before cancelling algebraic fractions.
  • Choose an equation method that matches its structure.
  • Use open or closed boundaries correctly for inequalities.
  • Graphs connect roots, intersections, gradients and areas to algebra.
  • Differentiation finds gradients and stationary points.
  • Inverse functions undo; composite functions apply one function after another.